4/5x^2+12=5

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Solution for 4/5x^2+12=5 equation: 



4/5x^2+12=5

We move all terms to the left:

4/5x^2+12-(5)=0



Domain of the equation: 5x^2!=0

x^2!=0/5

x^2!=√0

x!=0

x∈R



We add all the numbers together, and all the variables

4/5x^2+7=0

We multiply all the terms by the denominator


7*5x^2+4=0

Wy multiply elements

35x^2+4=0

a = 35; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·35·4
Δ = -560
Delta is less than zero, so there is no solution for the equation

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